Real Numbers Test

Real Numbers

This is Real Numbers Test-01 for CBSE class 10 Maths.. There are 15 questions in this test with each question having around four answer choices.

Questions & Answers

A number when divided by 61 gives 27 as quotient and 32 as remainder, then the number is:

Every positive even integer is of the form ____ for some integer ‘q’.

Every positive odd integer is of the form ________ where ‘q’ is some integer.

For any two positive integers a and b, there exist (unique) whole numbers q and r such that

A
$ a{\text{ }} = {\text{ }}bq{\text{ }} + {\text{ }}r, 0 \leqslant r < b. $
Correct
B
$ q{\text{ }} = {\text{ }}ar{\text{ }} + {\text{ }}b $ , $ 0 \leqslant r < b. $.
C
none of these
D
$b{\text{ }} = {\text{ }}aq{\text{ }} + {\text{ }}r$ , $0 \leqslant r < b.$

For any positive integer ‘a’ and 3, there exist unique integers ‘q’ and ‘r’ such that a = 3q + r where ‘r’ must satisfy

If $112 = q \times 6 + r,$ then the possible values of r are:

By Euclid’ division lemma $x = qy + r,x > y,$ the value of $q$ and $r$ for $x = 27$ and $y = 5$ are:

Every positive odd integer is of the form 2q + 1, where ‘q’ is some

Any ____________ is of the form 4q + 1 or 4q + 3 for some integer ‘q’.

The product of three consecutive positive integers is divisible by

The least number $n$ so that ${5^n}$ is divisible by 3, where $n$ is:

For every positive integer ‘n’, ${n^2} - n$ is divisible by

For every natural number ‘n’, ${6^n}$ always ends with the digit

If ${m^2}--{\text{ }}1$ is divisible by 8, then ‘m’ is

If two positive integers ‘m’ and ‘n’ can be expressed as $m = {x^2}{y^5}$ and $n = {x^3}{y^2}$,where ‘x’ and ‘y’ are prime numbers, then HCF(m, n) =