Class 12 Semiconductor Electronics CBSE Questions & Answers
Class 12 · Semiconductor Electronics
This is Physics Class 12 Semiconductor Electronics CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
In an N-P-N transistor, P-type crystal is
- Aemitter
- Bcollector
- Cgrid
- DbaseCorrect
2
In P-N- P transistor operating as an amplifier with common emitter configurations a change in base current from 100 mA to 200 mA produces a change in collector current from 10 mA to 18 mA. The current gain of transistor is
- A12.5 \( \times {\rm{ 1}}{0^{ - {\rm{3}}}}\)
- B80.0Correct
- C25.0 \( \times {\rm{ 1}}{0^{ - {\rm{3}}}}\)
- D98
3
A p- type semiconductor can be obtained by adding
- Aphosphorus to pure germanium
- Bgallium to pure siliconCorrect
- Cantimony to pure germanium
- Darsenic to pure silicon
4
To use a transistor as an amplifier
- Ano biasing voltage is required
- Bboth junctions are forward biased
- Cthe emitter- base junction is forward biased and the base – collector junction is reverse biasedCorrect
- Dboth junctions are reverse biased
5
When we apply reverse bias to a junction diode it
- Araises the potential barrierCorrect
- Blowers the potential barrier
- Cincreases the majority carrier current
- Dincreases the minority carrier current
6
Two identical P-N junctions may be connected in series with a battery in three ways as shown. The potential drops across the two P –N junctions are equal in

- Acircuit 1 only
- Bcircuit 3 and 1
- Ccircuit 1 and 2
- Dcircuit 2 and 3Correct
7
The depletion layer in the p-n junction is caused
- Adrift of electrons
- Bdrift of holes
- Cmigration of impurity ions
- Ddiffusion of carrier ionsCorrect
8
When a P- N junction is reversed biased, the flow of current across the junction is mainly due to
- Adrift of charges
- Bdepends upon the nature of material.
- Cdiffusion of charge carriersCorrect
- Dboth drift and diffusion of the charges
9
In the middle of the depletion layer of a reverse biased p-n-junction, the
- Aelectric field is maximumCorrect
- Bpotential is maximum
- Cpotential is zero
- Delectric field is zero
10
The difference in variation of resistance with temperature in a metal and semiconductor is due to
- Atype of bonding
- Bvariation in number of charge carries with temperature
- Ccrystal structureCorrect
- Dvariation of scattering with temperature
11
For a transistor, the value of \( \alpha \) is 0.9. The value of \(\beta \) will be
- A9
- B0.09
- C1.0Correct
- D0.9
12
In a transistor the value of \(\beta \) is 100, the value of \( \alpha \) is
- A0.1
- B0.99
- C1
- D0.01Correct
13
A hole diffuses from the p- side to the N- side in a P-N junction. This means that
- Aa bond is broken on the P- side and the electron freed from the bond jumps to
- Ba bond is broken on the N-side and the electrons freed from the bond jump to
- Ca bond is broken on the N- side and the electron freed from the bond jumps toCorrect
- Da conduction electron on the P – side jumps to a broken bond to complete it
14
Suitable impurities are added to a semiconductor depending upon its use. This is done to
- Aincrease its electrical resistivity.
- Bincrease its life
- Cenable it to withstand high voltage
- Dincrease its electrical conductivityCorrect
15
In case of diamond , the forbidden gap is about
- A8.2 eV
- B0.8eV
- C6.0eVCorrect
- D1.2 eV