Class 12 Communication Systems CBSE Questions & Answers
Class 12 · Communication Systems
This is Physics Class 12 Communication Systems CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
AM detection is
- Arecovering the modulating signal from the received signalCorrect
- Bfinding the type of modulation
- Cnone of these
- Ddetecting whether it is modulated
2
A rectifier and an envelope detector for AM uses
- Atransistors for rectification and zener diodes for storing the peaks
- Bnone of these
- Cdiodes for rectification and capacitors for storing the peaksCorrect
- Dopamps for rectification and zener diodes for storing the peaks
3
Which of the following frequencies will be suitable for beyond-the horizon communication using sky waves?
- A1000 GHz
- B10 kHz
- C1 GHz
- D10 MHzCorrect
4
Frequencies in the UHF range normally propagate by means of:
- AGround waves.
- BSky waves
- CSpace wavesCorrect
- DSurface waves.
5
Digital signals, (i) do not provide a continuous set of values, (ii) represent values as discrete steps, (iii) can utilize binary system, and (iv) can utilize decimal as well as binary systems. Which of the above statements are true?
- A(i) and (ii) only
- BAll of (i), (ii), (iii) and (iv).
- C(i), (ii) and (iii) but not (iv)Correct
- D(ii) and (iii) only
6
Is it necessary for a transmitting antenna to be at the same height as that of the receiving antenna for line-of-sight communication? A TV transmitting antenna is 81m tall. How much service area can it cover if the receiving antenna is at the ground level?
- ANo, 3345 \({\rm{k}}{{\rm{m}}^{\rm{2}}}\)
- BNo, 3258 \({\rm{k}}{{\rm{m}}^{\rm{2}}}\)Correct
- Cyes, 3000 \({\rm{k}}{{\rm{m}}^{\rm{2}}}\)
- DNo, 3000 \({\rm{k}}{{\rm{m}}^{\rm{2}}}\)
7
A carrier wave of peak voltage 12V is used to transmit a message signal. What should be the peak voltage of the modulating signal in order to have a modulation index of 75\(\% \)?
- A9 VCorrect
- B7 V
- C6 V
- D8 V
8
Multiplexing is a scheme for transmitting multiple signals at the same time e.g. speeches of ten persons in different rooms on the same channel. How many transmitters will be required in any multiplexing scheme?
- Atwo
- Bthree
- ConeCorrect
- Dten
9
In Amplitude modulation if one of the two side bands is removed by a filter is it possible to recover the modulating signal?
- AYesCorrect
- BNo if the signal is strong
- CYes if signal is weak
- DNo
10
Suppose that on an AM signal, the Maximum peak to peak voltage value read from the graticule on the oscilloscope screen is 5.9 divisions and the Minimum peak to peak voltage value is 1.2 divisions. What is the modulation index?
- A0.562
- B0.762
- C0.462
- D0.662Correct
11
A standard AM broadcast station is allowed to transmit modulating frequencies up to 5 kHz. If the AM station is transmitting on a frequency of 980 kHz, maximum and minimum upper and lower sidebands are
- A995 kHz, 985
- B985 kHz, 995
- C985 kHz, 975 kHzCorrect
- D975 kHz, 975
12
A standard AM broadcast station is allowed to transmit modulating frequencies up to 5 kHz. If the AM station is transmitting on a frequency of 980 kHz, total bandwidth occupied by the AM station is
- A10 kHzCorrect
- B15 kHz
- C14 kHz
- D12 kHz
13
A formula for computing the total power in an AM signal when the carrier power and the modulation index are known is PT = Pc \(\left( {1 + {{{m^2}} \over 2}} \right)\) . If the carrier of an AM transmitter is 1000 W and it is modulated 100 percent the total AM power is
- A1000 W
- B2000 W
- C500 W
- D1500 WCorrect
14
A formula for computing the total power in an AM signal when the carrier power and the modulation index are known is \({{\rm{P}}_{\rm{T}}} = {\rm{Pc}}\) \(\left( {1 + {{{m^2}} \over 2}} \right)\) . if the carrier of an AM transmitter has a power = 30 W and it is modulated 85 percent the total AM power is
- A44.8 W
- B42.8 W
- C40.8 WCorrect
- D46.8 W
15
A formula for computing the total power in an AM signal when the carrier power and the modulation index are known is \({{\rm{P}}_{\rm{T}}} = {\rm{ Pc}}\) \(\left( {1 + {{{m^2}} \over 2}} \right)\) . If the carrier of an AM transmitter has a power = 30 W and it is modulated 85 percent the power in one sideband is
- A7.2 W
- B5.4 WCorrect
- C8.1 W
- D6.4 W