CONSTRUCTIONS Test-05
CONSTRUCTIONS Test-05
This is CONSTRUCTIONS Test-05 for CBSE class 10 Maths.. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
If PT, QT are two tangents to a circle with centre O such that \(\angle PTQ = {42^o},\) then \(\angle POQ = \)

- A\({84^o}\)
- B\({48^o}\)
- C\({42^o}\)
- D\({138^o}\)Correct
2
In drawing the tangent to circle at a point on it without using the centre of the circle as shown in figure, T’PT is the tangent, because

- A\(\angle 2 = \angle 5\)Correct
- B\(\angle 2 = \angle 1\)
- C\(\angle 3 = \angle 4\)
- D\(\angle 3 = \angle 1\)
3
In the figure of Q. 5, if \({B_2}{C_2}||CB,\) then \({A_2}\) divides A’B in the ratio

- A1 : 3
- B1 : 2Correct
- C1 : 1
- D1 : 4
4
To draw a pair of tangents to a circle which are inclined to each other at an angle of \({80^ \circ }\), it is required to draw tangents at end points of those two radii of the circle, the angle between them should be
- A\({60^ \circ }\)
- B\({135^ \circ }\)
- C\({100^ \circ }\)Correct
- D\({90^ \circ }\)
5
A pair of tangents can be constructed from a point P to a circle of radius of radius 8 cm situated at a distance of ………... from the centre
- A10 cmCorrect
- B2 cm
- C7.5 cm
- D8.0 cm
6
To draw a pair of tangents to a circle which are inclined to each other at an angle of \({60^ \circ }\), it is required to draw tangents at end-points of those two radii of the circle, the angle between them should be
- A\({90^ \circ }\)
- B\({60^ \circ }\)
- C\({120^ \circ }\)Correct
- D\({135^ \circ }\)
7
To construct a cyclic quadrilateral ABCD in which \(\angle B = {90^o},\) if a circle on which points A, B, C and D lie, has to be drawn, the centre of this circle is
- Athe midpoint of diagonal ACCorrect
- Bthe point of intersection of diagonals AC and BD
- Cthe midpoint of diagonal BD
- Da point which lies neither on AC nor on BD
8
To construct a triangle similar to a given \(\Delta PQR\) with its sides \(\frac{3}{7}\) of the corresponding sides of \(\Delta PQR,\) first draw a ray QX such that \(\angle RQX\) is an acute angle and X lies on the opposite side of P with respect to QR. Then locate points \({Q_1},{Q_2},{Q_3}....\) on QX at equal distances and next step is to join:
- A\({Q_4}\;to\;R\)
- B\({Q_7}\;to\;R\)Correct
- C\({Q_3}\;to\;R\)
- D\({Q_{10}}\;to\;R\)
9
To construct a triangle similar to a given \(\Delta ABC\) with its sides \(\frac{5}{4}\) of the corresponding sides of \(\Delta ABC\), first draw ray AX such that \(\angle BAX\) is an acute angle and X is on the opposite side of C with respect to AB. Then locate the points \({A_1},{A_2},{A_3},...\) on AX at equal distances and next step is to join:
- A\({A_5}B\)
- B\({A_4}B\)Correct
- C\({A_5}C\)
- D\({A_4}C\)
10
To construct a triangle similar to a given \(\Delta ABC\) with its sides \(\frac{8}{5}\) of the corresponding sides of \(\Delta ABC\). Draw a ray BX such that \(\angle CBX\) is an acute angle and X is on the opposite side of \(\angle A\) with respect to BC. The minimum number of points to be located at equal distances on ray BX is:
- A8Correct
- B13
- C5
- D3
11
To construct a triangle similar to a given \(\Delta ABC\) with its sides \(\frac{4}{5}\) of the corresponding sides of \(\Delta ABC,\) first draw a ray BX such that \(\angle CBX\), is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points \({B_1},{B_2},{B_3},{B_4},{B_5}\) on BX at equal distances and join \({B_5}\) to C. Now, next step is to draw a line parallel to \({B_5}C\) and passing through:
- A\({B_4}\)Correct
- B\({B_3}\)
- C\({B_2}\)
- D\({B_5}\)
12
The construction of a triangle, similar and larger to a given triangle as per given scale factor m : n, is possible only when,
- Am> n
- Bm< nCorrect
- Cm = n
- DIndependent of scale factor
13
The construction of triangle, similar and smaller to a given triangle as per given scale factor x : y, is possible only when,
- AIndependent of scale factor
- Bx< yCorrect
- Cx = y
- Dx> y
14
To construct a triangle similar to a given \(\Delta \;ABC\) with its\(\frac{8}{5}\) of the corresponding sides of \(\Delta \;ABC,\) draw a ray BX such that \(\angle CBX\)is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is
- A3
- B5
- C13
- D8Correct
15
To divide a line segment AB in the ratio p : q ( p, q are positive integers), draw a ray AX so that \(\angle BAX\) s an acute angle and then mark points on ray AX at equal distances such that the minimum number of these points is :
- Ap + qCorrect
- Bpq
- Cgreater of p and q
- Dp + q – 1