Limits And Derivatives CBSE Questions & Answers
Limits And Derivatives
This is Mathematics Class 11 Limits and Derivatives CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
The derivative of \({\sec ^{ - 1}}\left( {{1 \over {2{x^2} - 1}}} \right)\) with respect to \(\sqrt {1 - {x^2}} at\;x = {1 \over 2}\) is
- A- 2
- B1
- C4Correct
- D2
2
\({d \over {dx}}\left( {{x \over 2}\sqrt {{x^2} + {a^2}} + {{{a^2}} \over 2}\log \left( {x + \sqrt {{x^2} + {a^2}} } \right)} \right)\) is equal to
- A\(\sqrt {{x^2} + {a^2}} \)Correct
- Bnone of these
- C\({1 \over {x + \sqrt {{x^2} + {a^2}} }}\)
- D\({1 \over {\sqrt {{x^2} + {a^2}} }}\)
3
\({d \over {dx}}\left( {x\sqrt {{a^2} - {x^2}} + {a^2}{{\sin }^{ - 1}}\left( {{x \over a}} \right)} \right)\) is equal to
- A\(2\sqrt {{a^2} - {x^2}} \)Correct
- B\(\sqrt {{a^2} - {x^2}} \)
- Cnone of these
- D\({1 \over {\log x}}\)
4
\({d \over {dx}}({\sin ^{ - 1}}(\sqrt {1 - {x^2})} )\)is equal to
- A\( - {x \over {\sqrt {1 - {x^2}} }}for\;0 < \left| x \right| < 1\)
- Bnone of these
- C\( - {1 \over {\sqrt {1 - {x^2}} }}for\;\left| x \right| < 1\)
- D\( - {x \over {\left| x \right|\sqrt {1 - {x^2}} }}for0 < \left| x \right| < 1\)Correct
5
\({d \over {dx}}({\cos ^{ - 1}}(\sqrt {1 - {x^2})} )\) is equal to
- A\({x \over {\left| x \right|\sqrt {1 - {x^2}} }}for\;0 < \left| x \right| < 1\)Correct
- Bnone of these
- C\({1 \over {\sqrt {1 - {x^2}} }}for\;0 < \left| x \right| < 1\)
- D\({1 \over {\sqrt {1 - {x^2}} }}for\;\left| x \right| < 1\)
6
\({d \over {dx}}({\sec ^{ - 1}}x)\) is equal to
- Anone of these
- B\({{ - 1} \over {x\sqrt {{x^2} - 1} }}for\left| x \right| > 1\)
- C\({1 \over {\left| x \right|\sqrt {{x^2} - 1} }}for\left| x \right| > 1\)Correct
- D\({1 \over {x\sqrt {{x^2} - 1} }}for\left| x \right| > 1\)
7
\({d \over {dx}}(\cos e{c^{ - 1}}x)\) is equal to
- A\({{ - 1} \over {x\sqrt {{x^2} - 1} }}for\left| x \right| > 1\)
- Bnone of these
- C\({{ - 1} \over {\left| x \right|\sqrt {{x^2} - 1} }}for\left| x \right| > 1\)Correct
- D\({1 \over {x\sqrt {{x^2} - 1} }}for\left| x \right| > 1\)
8
\({d \over {dx}}({\sin ^{ - 1}}(1 - x))\) is equal to
- A\({1 \over {\sqrt {2x - {x^2}} }}\)
- B\({1 \over {\sqrt {{x^2} - 2x} }}\)
- C\({{ - 1} \over {\sqrt {2x - {x^2}} }}\)Correct
- Dnone of these
9
\({{{d^2}} \over {d{x^2}}}({\cos ^{ - 1}}(1 - x))\) is equal to
- A\({{1 - x} \over {{{(2x - {x^2})}^{3/2}}}}\)
- B\({{x - 1} \over {{{(2x - {x^2})}^{3/2}}}}\)Correct
- C\({1 \over {2{{(2x - {x^2})}^{3/2}}}}\)
- Dnone of these
10
If y = \(\sqrt {x + \sqrt {x + \sqrt {x + ... + to\;\infty } } } \) then \({{dy} \over {dx}} = \)
- A\({x \over {y + 1}}\)
- B\({1 \over {2y - 1}}\)Correct
- C\(\sqrt {{x \over {y + 1}}} \)
- D\({1 \over {2y + 1}}\)
11
\(\left\{ \begin{gathered} x\;\;\;\;\;\;,\;\;0 \leq x < 1 \\ 3 - x\;,\;\;\;1 \leq x \leq 2 \\ \end{gathered} \right.,then\;at\) x = 1, f (x) is
- Acontinuous but not derivable
- Bcontinuous
- Cnot continuousCorrect
- Dcontinuous on left and discontinuous on right.
12
\(f(x) = \left\{ \begin{gathered} {x^3},\;\;\left| x \right| \leq 1 \\ x\;\;,\;\;\left| x \right| > 1 \\ \end{gathered} \right.then\;f(x)\;is\)
- Anot continuous at -1 and 1
- Bnot derivable at – 1 and 1Correct
- Cderivable at all x {tex} \in{tex} R
- Dnone of these
13
If x = f(t) and y = g (t), then \({{{d^2}y} \over {d{x^2}}}\) is qual to
- Anone of these
- B\({{g''(t)} \over {f''(t)}}\)
- C\({{g''(t)f'(t) - g'(t)f''(t)} \over {{{(f'(t))}^3}}}\)Correct
- D\({{g''(t)f'(t) - g'(t)f''(t)} \over {{{(f'(t))}^2}}}\)
14
\({\text{f }}\left( {\text{x}} \right){\text{ }} = {\text{ }}\left| {{\text{ }}\left[ {\text{x}} \right]{\text{ x }}} \right|{\text{ in }}--{\text{ 1}}\)\( \le \) x \( \le \) 2 is
- Adifferentiable at x = 0
- Bdiscontinuous at x = 0
- Ccontinuous at x = 2
- Dcontinuous at x = 0Correct
15
\({d \over {dx}}\left( {{{\tan }^{ - 1}}\left( {{{\sqrt x - \sqrt a } \over {1 + \sqrt {x\;a} }}} \right)} \right),x,a > 0,is\) s
- A\({\tan ^1}\sqrt x - {\tan ^{ - 1}}\sqrt a \)
- B\({1 \over {1 + x}} - {1 \over {1 + a}}\)
- C\({1 \over {1 + x}}\)
- D\({1 \over {2\sqrt x (1 + x)}}\)Correct