Areas Of Parallelograms And Triangles CBSE Questions & Answers
Areas Of Parallelograms And Triangles
This is Mathematics Class 09 Areas of Parallelograms and Triangles CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
ABCD is a parallelogram. O is any point on diagonal BD. If \(ar(\triangle DOP) = 8\;c{m^2},\) \(ar(\triangle BOS) = 3\,c{m^2}\) and \(ar(\triangle APS) = 6\,c{m^2},\)then \(ar(\parallel \;ABCD)\) is
- A\(45\;c{m^2}.\)
- B\(46\;c{m^2}.\)Correct
- C\(33\;c{m^2}.\)
- D\(34\;c{m^2}.\)
2
In the given figure, ABCD is a rectangle and EFGH is a trapezium DE = CH. If \(ar\;(ABCD) = 26\,c{m^2},\) then ar (EFGH) is
- A\(39\;c{m^2}.\)
- B\(52\;c{m^2}.\)
- C\(34\;c{m^2}.\)
- D\(26\;c{m^2}.\)Correct
3
ABCD, ABEF and AGHF are parallelograms. If \(ar\;(ABCD) = 23\;c{m^2},\) then ar (FGH) is
- A\(11.5\;c{m^2}.\)Correct
- B\(23\;c{m^2}.\)
- C\(12.5\;c{m^2}.\)
- D\(12\;c{m^2}.\)
4
ABCD is a parallelogram in which DC is produced to P such that DC = CP. AP intersects BC at Q. If \(ar\;(\triangle BQD) = 3\;c{m^2},\) then \(ar(\parallel \;ABCD)\) is
- A\(6\;c{m^2}.\)
- B\(12\;c{m^2}.\)
- C\(9\;c{m^{2.}}.\)Correct
- D\(15\;c{m^2}.\)
5
PQRS is a parallelogram whose diagonals PR and SQ intersect at O. A line segment through O meets PQ at A and SR at B. If \(ar\;(PQRS) = 25\;c{m^2},\) then ar (SBAP) is
- A\(12.5\;c{m^2}.\)Correct
- B\(12\;c{m^2}.\)
- C\(25\;c{m^2}.\)
- D\(50\;c{m^2}.\)
6
ABCD and ABFE are parallelograms as shown in the figure. If \(ar\;(ABCD) = 24\;c{m^2}\) and \(ar\;(ABFE) = 18\;c{m^2},\) then ar (EFCD) is
- A\(42\,c{m^2}.\)Correct
- B\(36\;c{m^2}.\)
- C\(33\,c{m^2}.\)
- D\(30\;c{m^2}.\)
7
PQRS is a trapezium. A is any point on PQ and \(AB\parallel QR.\) If \(ar\;(\triangle PBQ) = 17\,c{m^2},\) then \(ar\;(\triangle ASR)\)is
- A\(8.5\;c{m^2}.\)
- B\(18.5\;c{m^2}.\)
- C\(10\;c{m^2}.\)
- D\(17c{m^2}.\)Correct
8
PQRS is a trapezium. A line drawn parallel to QP through R meets a line parallel to RP drawn through S at X. If ar (PQRS) is 22 \(c{m^2}\) and \(ar\;(\triangle PQR) = 8\;c{m^2},\) then \(ar\;(\triangle PXR)\) is
- A\(15\;c{m^2}.\)
- B\(14\;c{m^2}.\)Correct
- C\(8\;c{m^2}.\)
- D\(15\;c{m^2}.\)
9
ABCD and FECG are parallelograms equal in area. If \(ar\;(\triangle AQE) = 12\;c{m^2},\) then \(ar\;(\parallel \;FGBQ)\) is
- A\(24\,c{m^2}.\)Correct
- B\(20\;c{m^2}.\)
- C\(12\;c{m^2}.\)
- D\(36\;c{m^2}.\)
10
ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q,. CQ : QP = 3 : 1. If \(ar(\triangle PBQ) = 10\,c{m^2},\) then \(ar\;(\parallel \;ABCD)\) is
- A\(130\;c{m^2}.\)
- B\(120\;c{m^2}.\)
- C\(160\;c{m^2}.\)Correct
- D\(90\;c{m^2}.\)
11
Medians of \(\triangle ABC\) intersects at G. If \(ar\;(\triangle ABC) = 27\;c{m^2},\) then \(ar\;(\triangle BGC)\) is
- A\(9\;c{m^2}.\)Correct
- B\(12\;c{m^2}.\)
- C\(6\;c{m^2}.\;\)
- D\(18\,c{m^2}.\)
12
In the given figure, QA = AB = BC = CR. If \(ar\;(\triangle PQR) = 24\;c{m^2},\) then \(ar\;(\triangle PAR)\) is
- A\(\;16\;c{m^2}.\)
- B\(12\;c{m^2}.\)
- C\(18\;c{m^2}.\)Correct
- D\(20\,c{m^2}.\)
13
D and E are mid-points of BC and AD respectively. If \(ar\;(\triangle AEC) = 4\;c{m^2},\) then \(ar\;(\triangle BEC)\) is
- A\(6\;c{m^2}.\)
- B\(8\,c{m^2}.\)Correct
- C\(\;4\;c{m^2}.\)
- D\(12\;c{m^2}.\)
14
ABCD is a parallelogram. M is any point on AD. P is the mid-point of BM. If the area of parallelogram \(ABCD = 28\;c{m^2},\) then the area of \(\triangle MPC\) is
- A\(16\;c{m^2}.\)
- B\(7c{m^2}.\)Correct
- C\(12\;c{m^2}.\)
- D\(14\;c{m^2}.\)
15
P is any point on the base BC of \(\triangle ABC.\) D is the mid-point of BC. DE is drawn parallel to PA, If \(ar\;(\triangle ABC) = 12\;c{m^2},\) then \(ar\;(\triangle EPC)\) is
- A\(6\,c{m^2}.\)Correct
- B\(9\;c{m^2}.\)
- C\(4\;c{m^2}.\)
- D\(8\;c{m^2}.\)