Laws Of Motion CBSE Questions & Answers
Laws Of Motion
This is Physics Class 11 Laws of Motion CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
Neglecting air resistance, in which of the following cases the net force acting on a stone of mass 0.1 kg non zero?
- Ajust after it is dropped from the window of a stationary train
- Blying on the floor of a train which is accelerating with 1 m \({{\rm{s}}^{ - {\rm{2}}}}\) , the stone being at rest relative to the trainCorrect
- Cjust after it is dropped from the window of a train accelerating with 1 m \({{\rm{s}}^{ - {\rm{2}}}}\)
- Djust after it is dropped from the window of a train running at a constant velocity of 36 km/h
2
Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is accelerating with 1 m \({{\rm{s}}^{ - {\rm{2}}}}\), the stone being at rest relative to the train. Neglect air resistance.
- A0.2 opposite to the direction of motion
- B1.0 N in the direction of motion
- C0.1 N opposite to the direction of motion
- D0.1 N in the direction of motionCorrect
3
One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v, T is the tension in the string, the net force on the particle directed towards the centre is
- A\({\rm{T}} - {{{\rm{m}}{{\rm{v}}^2}} \over {\rm{l}}}\)
- B\({\rm{T}} + {{{\rm{m}}{{\rm{v}}^2}} \over {\rm{l}}}\)
- CTCorrect
- D0
4
A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 m \({{\rm{s}}^{ - {\rm{1}}}}\). How long does the body take to stop?
- A6.0 sCorrect
- B7.0 s
- C4.0 s
- D5.0 s
5
A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m \({{\rm{s}}^{ - {\rm{1}}}}\) to 3.5 m \({{\rm{s}}^{ - {\rm{1}}}}\) in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?
- A0.09 m \({{\rm{s}}^{ - {\rm{2}}}}\), 0.12 N in the direction of motion
- B0.06 m \({{\rm{s}}^{ - {\rm{2}}}}\), 0.18 N in the direction of motionCorrect
- C0.08 m \({{\rm{s}}^{ - {\rm{2}}}}\), 0.14 N in the direction of motion
- D0.07 m \({{\rm{s}}^{ - {\rm{2}}}}\), 0.16 N in the direction of motion
6
A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.
- A16 N at an angle of 46\(^\circ \) to the 8 N force
- B14 N at an angle of 37\(^\circ \) to the 8 N force
- C10 N at an angle of 36\(^\circ \) to the 8 N forceCorrect
- D12 N at an angle of 38\(^\circ \) to the 8 N force
7
The driver of a three-wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to save the child. What is the average retarding force on the vehicle? The mass of the three-wheeler is 400 kg and the mass of the driver is 65 kg.
- A– 2.2 m \({{\rm{s}}^{ - {\rm{2}}}}\), 900 N
- B– 2.3 m \({{\rm{s}}^{ - {\rm{2}}}}\), 1000 N
- C– 2.5 m\({{\rm{s}}^{ - {\rm{2}}}}\) , 1200 NCorrect
- D– 2.4 m \({{\rm{s}}^{ - {\rm{2}}}}\), 1100 N
8
A rocket with a lift-off mass 20,000 kg is blasted upwards with an initial acceleration of 5.0 m s-2. Calculate the initial thrust (force) of the blast.
- A300000 NCorrect
- B350000 N
- C365000 N
- D378000 N
9
A body of mass 0.40 kg moving initially with a constant speed of 10 m \({{\rm{s}}^{ - {\rm{2}}}}\) to the north is subject to a constant force of 8.0 N directed towards the south for 30 s. Take the instant the force is applied to be t = 0, the position of the body at that time to be x = 0, and predict its position at t = –5 s.
- A-50 mCorrect
- B50 m
- C-55 m
- D-60 m
10
A body of mass 0.40 kg moving initially with a constant speed of 10 m \({{\rm{s}}^{ - {\rm{1}}}}\) to the north is subject to a constant force of 8.0 N directed towards the south for 30 s. Take the instant the force is applied to be t = 0, the position of the body at that time to be x = 0, and predict its position at t = –25 s.
- A-8.0 km
- B-7 km
- C-6 kmCorrect
- D-7.5 km
11
A body of mass 0.40 kg moving initially with a constant speed of 10 m \({{\text{s}}^{ - {\text{1}}}}\) to the north is subject to a constant force of 8.0 N directed towards the south for 30 s. Take the instant the force is applied to be t = 0, the position of the body at that time to be x = 0, and predict its position at t = –100 s
- A-50 kmCorrect
- B-55 km
- C-60 km
- D-67 km
12
A truck starts from rest and accelerates uniformly at 2.0 m \({{\rm{s}}^{ - {\rm{2}}}}\). At t = 10 s, a stone is dropped by a person standing on the top of the truck (6 m high from the ground). What is the magnitude of velocity (in m \({{\rm{s}}^{ - {\rm{1}}}}\) ) of the stone at t = 11s? (Neglect air resistance.)
- A19.6
- B18.5
- C22.4Correct
- D21.0
13
A truck starts from rest and accelerates uniformly at 2.0 m \({{\rm{s}}^{ - {\rm{2}}}}\). At t = 10 s, a stone is dropped by a person standing on the top of the truck (6 m high from the ground). What is the magnitude of acceleration (in m \({{\rm{s}}^{ - {\rm{2}}}}\) ) of the stone at t = 11s? (Neglect air resistance.)
- A10.0Correct
- B8
- C14
- D12
14
A bob of mass 0.1 kg hung from the ceiling of a room by a string 2 m long is set into oscillation. The speed of the bob at its mean position is 1 m \({{\rm{s}}^{ - {\rm{1}}}}\).What is the trajectory of the bob if the string is cut when the bob is at one of its extreme positions
- Abob will go upwards
- Bbob will fall vertically downwardsCorrect
- Cbob will go downwards at an angle
- Dbob will go down in a parabolic path
15
A bob of mass 0.1 kg hung from the ceiling of a room by a string 2 m long is set into oscillation. The speed of the bob at its mean position is 1 m \({{\rm{s}}^{ - {\rm{1}}}}\).What is the trajectory of the bob if the string is cut when the bob is at its mean position.
- Abob will fall vertically downwards
- Bbob will fall vertically downwards
- Cbob will go down in a parabolic pathCorrect
- Dbob will go upwards