Constructions CBSE Questions & Answers
Constructions
This is Mathematics Class 09 Constructions CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
In the construction of the perpendicular bisector of a given line segment, as \(shown\;in\;the\;figure\;below\;\triangle PMA \cong \triangle PMB\;by\;which\;congruence\;criterion?\)
- ARHS
- BSASCorrect
- CAAS
- DSSS
2
On a ray AB with initial point A, Taking A as centre and some radius, draw an arc of a circle, which intersects AB, say at a point D. Taking D as centre and with the same radius as before, draw an arc intersecting the previously drawn arc, say at a point E. Draw the ray AC passing through E. Then, the measure of \(\angle CAB\) is
- A\({30^0}\)
- B\({15^0}\)
- C\({60^0}\)Correct
- D\({45^0}\)
3
If a \({60^0}\) angle is bisected twice what will be measure of each angle that is constructed ?
- A\({30^0}\)
- B\({15^0}\)Correct
- C\({5^0}\)
- D\({45^0}\)
4
In the following below PR is the perpendicular bisector of a line segment AB = 16 cm, then which of the following is true ?
- AOP > OR
- BPB = PR
- CPA = PR
- DPA = PBCorrect
5
An external bisector of an angle measuring \({70^0}\) will divide the angle into two angles measuring
- A\({70^0}\)
- B\({35^0}\)
- C\({110^0}\)
- D\({55^0}\)Correct
6
In \(\triangle \) ABC, which of the following information is needed to construct it if it is known that measure of \(\angle B = 60\) and BC = 6 cm :
- ACA + AB
- BAll of the aboveCorrect
- CAB + BC
- DBC + CA
7
Which of these triangles are possible to construct by knowing only its altitude?
- ARight angled triangle
- BIsosceles triangle
- CEquilateral triangleCorrect
- DAny triangle
8
To construct a \(\triangle \) ABC in which BC = 10 cm and \(\angle B = 60\) degrees and AB + AC = 14 cm, then the length of BD used for construction :
- A7 cm
- B20 cm
- C10 cm
- D14 cmCorrect
9
With the help of a ruler and a compass it is not possible to construct an angle of :
- A\({22.5^0}\)
- B\({37.5^0}\)
- C\({50^0}\)Correct
- D\({67.5^0}\)
10
The construction of a triangle ABC, given that BC = 3 cm, \(\angle C = {30^0}\) is possible when sum of AB and AC is equal to :
- A2.8 cm
- B3.2 cmCorrect
- C3 cm
- D2 cm
11
In the following figure, AD = AC + BC. Find the relation between \(\angle 1\;and\;\angle 2:\)
- A\(\angle 1 > \angle 2\)
- B\(\angle 1 < \angle 2\)
- C\(\angle 1 + \angle 2 = {90^0}\)
- D\(\angle 1 = \angle 2\)Correct
12
In figure, LM is an arc of a circle having radius = \({\rm{r}}\). If AL = AM = AN = LM = \({\rm{r}}\) And \(LN = {1 \over 2}LM.\) Then \(\angle CAB = \)
- A\({15^0}\)
- B\({30^0}\)Correct
- C\({45^0}\)
- D\({60^0}\)
13
In figure , \(\angle BAC = {90^0}.\)\(\angle BAD = \angle CAD\;and\;\angle DAE = \angle CAE.\;Here,\;\angle BAE = \)
- A\(67{1 \over 2}^\circ \)Correct
- B\({65^0}\)
- Cnone of these.
- D\({75^0}\)
14
With the help of a ruler and a compass it is not possible to construct an angle of
- A\({37.5^0}\)
- B\({80^0}\)Correct
- C\({67.5^0}\)
- D\({22.5^0}\)
15
The construction of a triangle ABC, given that \(BC = 3\;cm,\;\angle C = {60^0},\) is possible when difference of AB and AC is equal to
- A2.8 cmCorrect
- B3.1 cm
- C3 cm
- D3.2 cm