Number Systems CBSE Questions & Answers
Number Systems
This is Mathematics Class 09 Number Systems CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
Which of the following is an irrational number?
- A\(2.7\overline {17} \)
- B2.717
- C2.717171717171………
- D2.717117111711117…………Correct
2
Which of the following is an rational number?
- A\(\sqrt {31} \)
- B0.323223222322223…….
- C\(\sqrt {180} \)
- D\(\sqrt {196} \)Correct
3
Every rational number is
- Aa real numberCorrect
- Ban integer
- Ca natural number
- Da whole number
4
The decimal representation of a rational number is
- Aalways non-terminating
- Beither terminating or repeatingCorrect
- Ceither terminating or non-repeating
- Dalways terminating
5
The decimal representation of an irrational number is
- Aeither terminating or non-repeating
- Balways terminating
- Calways non-terminating
- Dneither terminating nor repeatingCorrect
6
Between any two rational numbers there
- Aare many rational numbersCorrect
- Bis no irrational number
- Care exactly two rational numbers
- Dis no rational number
7
The product of two irrational numbers is
- Aalways irrational
- Balways an integer
- Ceither irrational or rationalCorrect
- Dalways rational
8
The sum of two irrational numbers is
- Aalways irrational
- Beither irrational or rationalCorrect
- Calways rational
- Dalways an integer
9
The difference of two irrational numbers is
- Aalways an integer
- Beither irrational or rationalCorrect
- Calways rational
- Dalways irrational
10
Which of the following is a true statement?
- A\(\pi \) is rational and \({{22} \over 7}\) is rational
- B\(\pi \) is rational and \({{22} \over 7}\) is irrational
- C\(\pi \) is irrational and \({{22} \over 7}\) is irrational
- D\(\pi \) is irrational and \({{22} \over 7}\) is rationalCorrect
11
A rational number between \(\sqrt 3 \) and \(\sqrt 5 \) is
- A2.1Correct
- B\({1 \over 2}(\sqrt 3 + \sqrt 5 )\)
- C3.1
- D\({1 \over 2}(\sqrt 3 - \sqrt 5 )\)
12
\({(1296)^{{{ - 1} \over 4}}}\)=
- A6
- B\( - {1 \over 6}\)
- C\({1 \over 6}\)Correct
- D-6
13
\(\sqrt {12} \times \sqrt {15} \) =
- A5
- B\(5\sqrt 6 \)
- C6
- D\(6\sqrt 5 \)Correct
14
\({(625)^{0.16}} \times {(625)^{0.09}}\) =
- A125
- B625
- C5Correct
- D25
15
If \(\sqrt 5 = 2.236\), then \({1 \over {\sqrt 5 }}\) =
- A0.4472Correct
- B0.04472
- C4.472
- D44.72