Herons Formula CBSE Questions & Answers
Herons Formula
This is Mathematics Class 09 Herons Formula CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
The area of a triangle with base 8 cm and height 10 cm is
- A80 \(c{m^2}\)
- B18 \(c{m^2}\)
- C40 \(c{m^2}\)Correct
- D20 \(c{m^2}\)
2
The base of a right triangle is 8 cm and hypotenuse is 10 cm. Its area will be
- A80 \(c{m^2}\)
- B40 \(c{m^2}\)
- C24 \(c{m^2}\)Correct
- D48 \(c{m^2}\)
3
A triangle ABC in which AB = AC = 4 cm and \(\angle A = {90^o}\), has an area of
- A12 \(c{m^2}\)
- B4 \(c{m^2}\)
- C8 \(c{m^2}\)Correct
- D16 \(c{m^2}\)
4
If the side of an equilateral triangle is 4 cm, then its area is
- A\(4\sqrt 3 \;c{m^2}\)Correct
- B\(12\sqrt 3 \;c{m^2}\)
- C\(8\sqrt 3 \;c{m^2}\)
- D\(16\sqrt 3 \;c{m^2}\)
5
If the perimeter of an equilateral triangle is 24 m, then its area is
- A\(8\sqrt 3 \;{m^2}\)
- B\(20\sqrt 3 \;{m^2}\)
- C\(24\sqrt 3 \;{m^2}\)
- D\(16\sqrt 3 \;{m^2}\)Correct
6
The length of each side of an equilateral triangle having an area of \(25\sqrt 3 \;c{m^2}\) is
- A10 cmCorrect
- B25 cm
- C5 cm
- D15 cm
7
If the area of an equilateral triangle is \(36\sqrt 3 \;c{m^2}\) , then the perimeter of the triangle is
- A\(12\sqrt 3 \;cm\)
- B36 cmCorrect
- C12 cm
- D18 cm
8
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 70 paise per \(c{m^2}\) is
- ARs 16
- BRs 17
- CRs 7
- DRs 16.80Correct
9
The perimeter of a rhombus is 20 cm. If one of its diagonals is 6 cm, then its area is
- A36 \(c{m^2}\)
- B24 \(c{m^2}\)Correct
- C28 \(c{m^2}\)
- D20 \(c{m^2}\)
10
The area of a rhombus of 96\(c{m^2}\). If one of its diagonals is 16 cm, then the length of its side is
- A6 cm
- B12 cm
- C10 cmCorrect
- D8 cm
11
An isosceles right triangle has area 8\(c{m^2}\). The length of the hypotenuse is
- A\(\sqrt {32} \;cm\)Correct
- B6 cm
- C4 cm
- D8 cm
12
The area of an isosceles triangle having base 24 cm and length of one of the equal sides 20 cm is
- A240 \(c{m^2}\)
- B196 \(c{m^2}\)
- C192 \(c{m^2}\)Correct
- D480 \(c{m^2}\)
13
The perimeter of an isosceles triangle is 32 cm. the ratio of the equal side to its base is 3 : 2. Then area of the triangle is
- A\(32\sqrt 2 \;c{m^2}\)Correct
- B16 \(c{m^2}\)
- C\(16\sqrt 2 \;c{m^2}\)
- D32 \(c{m^2}\)
14
If the perimeter and base of an isosceles triangle are 11 cm and 5 cm respectively, then its area is
- A\({5 \over 2}\sqrt {11} \;c{m^2}\)
- B\({5 \over 8}\sqrt {11} \;c{m^2}\)
- C\({5 \over 4}\sqrt {11} \) \(c{m^2}\)Correct
- D\(5\sqrt {11} \) \(c{m^2}\)
15
The area of a regular hexagon of side 4 cm is
- A\(24\sqrt 3 \;c{m^2}\)Correct
- B\(6\sqrt 3 \;c{m^2}\)
- C\(16\sqrt 3 \;c{m^2}\)
- D\(4\sqrt 3 \;c{m^2}\)