Statistics CBSE Questions & Answers
Statistics
This is Mathematics Class 09 Statistics CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
Vihaan has marks of 92, 85, and 78 in three mathematics tests. In order to have an average of exactly 87 for the four math tests, he should obtain
- A91 marks
- B90 marks
- C92 marks
- D93 marksCorrect
2
If \(\bar x\) is the mean of \({x_1},{x_2},...,{x_n},\bar y\) is the mean of \({y_1},{y_2}...,{x_n},...,{y_{n'}}\) then \(\bar z\) th mean of \({x_1},{x_2}...,{x_n},{y_1},{y_2},...,{y_n}\) is equal to
- A\({{\bar x + \bar y} \over {2n}}\)
- B\({{\bar x + \bar y} \over n}\)
- C\(\bar x + \bar y\)
- D\({{\bar x + \bar y} \over 2}\)Correct
3
If \(\bar x\) is the mean of \({x_1},{x_2},...,{x_n}\) then for a \( \ne \)0, the mean of \(a{x_1},a{x_2},...,a{x_n},\) \({{{x_1}} \over a},{{{x_2}} \over a},...,{{{x_n}} \over a}\) is
- A\(\left( {a + {1 \over a}} \right){{\bar x} \over n}\)
- B\(\left( {a + {1 \over a}} \right)\bar x\)
- C\(\left( {a + {1 \over a}} \right){{\bar x} \over 2}\)Correct
- D\({{\left( {a + {1 \over a}} \right)\bar x} \over {2n}}\)
4
If the mean of x and \({1 \over x}\) is M, then the mean of \({x^2}\) and \({1 \over {{x^2}}}\) is
- A\(2{M^2} - 1\)Correct
- B\(2{M^2} + 1\)
- C2M + 1
- D2M – 1
5
If the mean of x and \({1 \over x}\) is M, then the mean of \({x^3}\) and \({1 \over {{x^3}}}\) is
- A\(3{M^3} - 4M\)
- B\(4{M^3} + 3M\)
- C\(4{M^3} - 3M\)Correct
- D\(3{M^3} + 4M\)
6
The mean of six numbers is 23. If one of the numbers is excluded, the mean of the remaining numbers becomes 20. The excluded number is
- A38Correct
- B37
- C39
- D36
7
The mean of five observations is 15. If the mean of first three observations is 14 and that of last three is 17, then the third observation is
- A31
- B18Correct
- C32
- D29
8
The mean of 50 observations is 39. If one of the observations which was 23 was replaced by 43, the resulting mean will be
- A38.4
- B40.3
- C39.4Correct
- D39
9
There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. The mean of the given number is
- A56.5Correct
- B52.5
- C49.5
- D47.5
10
The mean of n observations is\(\bar x\). If the first item is increased by 1, second by 2, third by 3 and so on, then the new mean is
- A\(\bar x + {{n + 1} \over 2}\)Correct
- B\(\bar x + {n \over 2}\)
- C\(\bar x + {{n(n + 1)} \over 2}\)
- D\(\bar x + n\)
11
The mean of the above frequency distribution is 3.5, then the value of x is
- A2
- B3Correct
- C4
- D5
12
If the mean of the observations: x, x + 3, x + 5, x + 7, x + 10 is 9, the mean of last three observations is
- A\(10{2 \over 3}\)
- B\(10{1 \over 3}\)
- C\(11{2 \over 3}\)
- D\(11{1 \over 3}\)Correct
13
The traffic police recorded the speed (in km/h) of 10 motorists as 48, 52, 57, 55, 42, 39, 60, 49, 53 and 47. Later an error in recording instrument was found. If the instrument has recorded the speed 5 km/h less in each case, then the correct average speed of the motorists is
- A54.5 km/h
- B52.5 km/h
- C50.2 km/h
- D55.2 km/hCorrect
14
The difference between the mean and median of first five prime numbers is
- A0.8
- B1
- C0.6Correct
- D0.4
15
When the data consists of 3, 4, 5, 4, 3, 4, 5, which statement is true ?
- Amean > mode
- BMean = modeCorrect
- CMedian < mode
- DMean > median