Lines And Angles CBSE Questions & Answers
Lines And Angles
This is Mathematics Class 09 Lines and Angles CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
If two angles are supplementary and the larger is 20\(^0\) less then three times the smaller, then the angles are :-
- A140\(^0\), 40\(^0\)
- B\(62\frac{1}{2}\) \(^0\), \(27\frac{1}{2}\) \(^0\)
- C\(72\frac{1}{2}\) \(^0\), \(17\frac{1}{2}\) \(^0\)
- D130\(^0\), 50\(^0\)Correct
2
In the adjoining figure, if DE \(\parallel \) BC, then the values of x and y are :-

- Ax = 25\(^0\), y = 85\(^0\)
- Bx = 26\(^0\), y – 138\(^0\)
- Cx = 25\(^0\), y = 135\(^0\)Correct
- Dx = 20\(^0\), y = 120\(^0\)
3
In the adjoining figure, if A = 40\(^0\), B = 95\(^0\) and D = 60\(^0\), then E is equal to :-

- A65\(^0\)
- B75\(^0\)Correct
- C85\(^0\)
- D55\(^0\)
4
In the adjoining figure, the bisectors of \(\angle \)CBD and \(\angle \)BCE meet at the point O. If \(\angle \)BAC = 70\(^0\), then \(\angle \)BOC is equal to :-

- A11\(^0\)
- B70\(^0\)
- C55\(^0\)Correct
- D35\(^0\)
5
In the adjoining figure, BE and CE are bisectors of \(\angle \)ABC and \(\angle \)ACD respectively. If \(\angle \)BEC = 25\(^0\), then \(\angle \)BAC is equal to :-

- A\(25\frac{1}{2}\) \(^0\)
- B50\(^0\)Correct
- C\(12\frac{1}{2}\) \(^0\)
- D65\(^0\)
6
In the given figure AB is a mirror, PQ is the incident ray and QR is the reflected ray. If \(\angle \)PQR = 108\(^0\), then \(\angle \)AQP = ?

- A36\(^0\)Correct
- B18\(^0\)
- C54\(^0\)
- D72\(^0\)
7
In the given figure, AB \(\parallel \) CD and O is a point joined with B and D, as shown in the figure such that \(\angle \)ABO = 35\(^0\) and \(\angle \)CDO = 40\(^0\). Reflex \(\angle \)BOD = ?

- A265\(^0\)
- B255\(^0\)
- C285\(^0\)Correct
- D275\(^0\)
8
In the given figure, AB \(\parallel \) CD. If \(\angle \)BAO = 60\(^0\) and \(\angle \)OCD = 110\(^0\), then \(\angle \)AOC = ?

- A70\(^0\)
- B40\(^0\)
- C50\(^0\)Correct
- D60\(^0\)
9
In the given figure, AB \(\parallel \) CD. If \(\angle \)AOC = 30\(^0\) and \(\angle \)OAB = 100\(^0\). then \(\angle \)OCD = ?

- A150\(^0\)
- B80\(^0\)
- C130\(^0\)Correct
- D100\(^0\)
10
In the given figure, AB \(\parallel \) CD, If \(\angle \)CAB = 80\(^0\) and \(\angle \)EFC = 25\(^0\), then \(\angle \)CEF = ?

- A45\(^0\)
- B75\(^0\)
- C65\(^0\)
- D55\(^0\)Correct
11
In the given figure, AB \(\parallel \) CD, If \(\angle \)APQ = 70\(^0\) and \(\angle \)PRD = 120\(^0\), then \(\angle \)QPR = ?

- A50\(^0\)Correct
- B40\(^0\)
- C35\(^0\)
- D60\(^0\)
12
In the given x = ?

- A\(\alpha \, + \,\beta \, + \,\gamma \)Correct
- B\(\alpha \, + \,\beta \, - \,\gamma \)
- C\(\alpha \, - \,\beta \, - \,\gamma \)
- D\(\alpha \, + \,\gamma \, - \,\beta \)
13
If \(\angle \)A = 4\(\angle \)B = 6\(\angle \)C, then A : B : C + ?
- Ait is 2 : 3 : 4
- Bit is 6 : 4 : 3
- Cit is 4 : 3 : 2Correct
- Dit is 3 : 4 : 6
14
Side BC of \(\Delta\)ABC has been produced to D on left hand side and to E on right hand side such that \(\angle \)ABD = 125\(^0\) and \(\angle \)ACE = 130\(^0\) . Then \(\angle \)A = ?

- A55\(^0\)
- B65\(^0\)
- C75\(^0\)Correct
- D50\(^0\)
15
In the given figure, \(\angle \)BAC = 30\(^0\), \(\angle \)ABC = 50\(^0\) and \(\angle \)CDE = 40\(^0\). Then \(\angle \)AED = ?

- A100\(^0\)
- B110\(^0\)
- C120\(^0\)Correct
- D80\(^0\)