QUADRATIC EQUATIONS Test
QUADRATIC EQUATIONS
This is QUADRATIC EQUATIONS Test-01 for CBSE class 10 Maths.. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
A quadratic equation whose one root is 3 is
- A\({x^2} + 6x - 5 = 0\)
- B\({x^2} - 6x - 5 = 0\)
- C\({x^2} - 5x - 6 = 0\)
- D\({x^2} - 5x + 6 = 0\)Correct
2
One of the roots of the quadratic equation \({a^2}{x^2} - 3abx + 2{b^2} = 0\) is
- A\(\frac{{2a}}{b}\)
- B\(\frac{{ - 2a}}{b}\)
- C\(\frac{{2b}}{a}\)Correct
- D\(\frac{{ - 2b}}{a}\)
3
The quadratic equation whose roots are \(7 + \sqrt 3 \) and \(7 - \sqrt 3 \) is
- A\({x^2} - 14x - 46 = 0\)
- B\({x^2} - 14x + 46 = 0\)Correct
- C\({x^2} + 14x - 46 = 0\)
- D\({x^2} + 14x + 46 = 0\)
4
If x = 2 is a root of the quadratic equation 3x2 – px – 2 = 0, then the value of ‘p’ is
- A3
- B0
- C1
- D5Correct
5
\(5{x^2} + 8x + 4 = 2{x^2} + 4x + 6\) is a
- Alinear equation
- Bconstant
- Cquadratic equationCorrect
- Dcubic equation
6
The product of two consecutive integers is 240. The quadratic representation of the above situation is
- A\(x(x + 1) = 240\)Correct
- B\(5{x^2} + 8x + 4 = 2{x^2} + 4x + 6\)
- C\({x^2} + (x + 1) = 240\)
- D\(x{(x + 1)^2} = 240\)
7
The sum of two numbers is 17 and the sum of their reciprocals is \(\frac{{17}}{{62}}\). The quadratic representation of the above situation is
- A\(\frac{1}{x} - \frac{1}{{17 - x}} = \frac{{17}}{{62}}\)
- B\(\frac{1}{x} + \frac{1}{{x + 17}} = \frac{{17}}{{62}}\)
- C\(\frac{1}{x} + \frac{1}{{17 - x}} = \frac{{17}}{{62}}\)Correct
- D\(\frac{1}{{x(17 - x)}} = \frac{{17}}{{62}}\)
8
Which of the following is a quadratic equation?
- A\((k + 1){x^2} + \frac{3}{2}x - 5 = 0\), where k = – 1
- B\({x^3} - {x^2} = {(x - 1)^3}\)Correct
- C\( - 2{x^2} = (5 - x)\left( {2x - \frac{2}{5}} \right)\)
- D\({x^2} + 2x + 1 = {(4 - x)^2} + 3\)
9
Which of the following is not a quadratic equation?
- A\(2{(x - 1)^2} = 4{x^2} - 2x + 1\)
- B\({\left( {\sqrt 2 x + \sqrt 3 } \right)^2} + {x^2} = 3{x^2} - 5x\)Correct
- C\({({x^2} + 2x)^2} = {x^4} + 3 + 4{x^3}\)
- D\(2x - {x^2} = {x^2} + 5\)
10
If p = – 7 and q = 12 and \({x^2} + px + q = 0\), then the value of ‘x’ is
- A– 3 and 4
- B3 and – 4
- C– 3 and – 4
- D3 and 4Correct
11
The hypotenuse of a right triangle is 6m more than twice the shortest side. The third side is 2m less than the hypotenuse. The representation of the above situation in the form of a quadratic equation is
- Anone of these
- B\({(2x + 6)^2} = {x^2} - {(2x + 4)^2}\)
- C\({(2x + 6)^2} + {x^2} = {(2x + 4)^2}\)
- D\({(2x + 6)^2} = {x^2} + {(2x + 4)^2}\)Correct
12
The roots of a quadratic equation \({x^2} - 4px + 4{p^2} - {q^2} = 0\) are
- A2p – q, 2p – q
- B2p + q, 2p – qCorrect
- C2p + q, 2p + q
- Dp + 2q, p – 2q
13
The two numbers whose sum is 27 and their product is 182 are
- A12 and 13
- B14 and 15
- C12 and 15
- D13 and 14Correct
14
If the sum of a number and its reciprocal is \({\text{2}}\frac{{\text{1}}}{{\text{2}}}\), then the numbers are
- A\({\text{3 and }}\frac{{\text{1}}}{{\text{3}}}{\text{ }}\)
- Bnone of these
- C\({\text{2 and }}\frac{{\text{1}}}{{\text{2}}}{\text{ }}\)Correct
- D\({\text{1 and }}\frac{{\text{3}}}{{\text{2}}}{\text{ }}\)
15
The common root of \(2{x^2} + x - 6 = 0\) and \({x^2} - 3x - 10 = 0\) is
- A\(\frac{3}{2}\)
- B– 2Correct
- C2
- D5