COORDINATE GEOMETRY Test
COORDINATE GEOMETRY
This is COORDINATE GEOMETRY Test-02 for CBSE class 10 Maths.. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
If A and B are the points ( – 6, 7) and ( – 1, – 5) respectively, then the distance 2AB is equal to 26 units 13 units 15 units 20 units 2AB = \(2\sqrt {{{\left( { - 1 + 6} \right)}^2} + {{\left( { - 5 - 7} \right)}^2}} \) = \(2\sqrt {25 + 144} \) = \(2\sqrt {169} \) = 26 units
- A26 unitsCorrect
- B13 units
- C15 units
- D20 units
2
If P(x, y) is any point on the line joining the points A(a, 0) and B(0, b), then
- A\(\frac{x}{a} - \frac{y}{b} = 0\)
- B\(\frac{x}{a} + \frac{y}{b} = 1\)Correct
- C\(\frac{x}{a} - \frac{y}{b} = 1\)
- D\(\frac{x}{a} + \frac{y}{b} = 0\)
3
The vertices of a quadrilateral are (1, 7), (4, 2), ( – 1, – 1) and ( – 4, 4). The quadrilateral is a
- Aparallelogram
- BsquareCorrect
- Cnone of these
- Drectangle
4
If A is point on the x – axis whose abscissa is 5 and B is the point (1, – 3), then the distance AB is
- A8 units
- B5 unitsCorrect
- C9 units
- D25 units
5
The distance of the point ( – 5, 12) from the y – axis is
- A13 units
- B5 unitsCorrect
- C– 5 units
- D12 units
6
If one end of a diameter of a circle is (4, 6) and the centre is ( – 4, 7), then the other end is
- A(8, – 12)
- B(8, – 6)
- C(8, 10)
- D( – 12, 8)Correct
7
The distance between the points (a, b) and ( – a, – b) is
- A\(2b\)
- B2a
- C\(\sqrt 2 a\)
- D\(2\sqrt {{a^2} + {b^2}} \)Correct
8
The points A( – 1, 0), B(3, 1), C(2, 2) and D( – 2, 1) are the vertices of a
- Anone of these
- BSquare
- CRectangle
- DParallelogramCorrect
9
The points A(1, 2), B(5, 4), C(3, 8) and D( – 1, 6) are the vertices of a
- ARectangle
- BParallelogram
- CSquareCorrect
- DRhombus
10
The points A(4, – 1), B(6, 0), C(7, 2) and D(5, 1) are the vertices of a
- ASquare
- BRhombusCorrect
- CRectangle
- DParallelogram
11
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
- A9 units
- B15 units
- C10 units
- D12 unitsCorrect
12
AOBC is a rectangle whose three vertices are A(0, 3), O(0, 0) and B(5, 0). The length of its diagonal is

- A\(\sqrt {34} \) unitsCorrect
- B\(2\sqrt {34} \) units
- C3 units
- D4 units
13
(0, 3), (4, 0) and ( – 4, 0) are the vertices of
- Aa right triangle
- Ban equilateral triangle
- Ca scalene triangle
- Dan isosceles triangleCorrect
14
Radius of circumcircle of a triangle ABC is \(5\sqrt {10} \) units. If point P is equidistant from A (1, 3), B\(\left( { - 3,5} \right)\) and C\(\left( {5, - 1} \right),\) then AP =
- A25 units
- B5 units
- C\(5\sqrt {10} \) unitsCorrect
- D\(5\sqrt 5 \) units
15
The co – ordinates of the point which is equidistant from the three vertices of a \(\Delta AOB\) with vertices A(0, 2y), B(2x, 0) and O(0, 0) is
- A(x, y)Correct
- B(y, x)
- C(0, 0)
- D\(\left( {\frac{x}{2},\frac{y}{2}} \right)\)