Mathematical Reasoning CBSE Questions & Answers
Mathematical Reasoning
This is Mathematics Class 11 Mathematical Reasoning CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
\( \sim p \vee \sim q\)is logically equivalent to
- A\( \sim p \to \sim q\)
- B\(p \to \sim q\)Correct
- C\(p \leftrightarrow q\)
- D\(p \to \sim q\)
2
\( \sim (p \wedge q)\) is logically equivalent to
- A\( \sim p \leftrightarrow \sim q\)
- B\( \sim p \vee \sim q\)Correct
- C\( \sim p \to \sim q\)
- D\( \sim p \to q\)
3
Which of the following is logically equivalent to \(p \leftrightarrow q\) ?
- A\((p \to q) \wedge (q \to p)\)Correct
- B\((p \wedge q) \wedge (q \to p)\)
- C\((p \wedge q) \wedge (q \vee p)\)
- D\((p \to q) \vee (q \to p)\)
4
If \(p \to (q \vee r)\) is false , then the truth values of p , q , r are respectively
- AF,T,T
- BT,T,F
- CT,F,FCorrect
- DF,F,F
5
The compound statement \(p \to ( \sim p \vee q)\) is false , then the truth values of p and q are respectively
- AF,F
- BT,FCorrect
- CF,T
- DT,T
6
The false statement in the following is
- A)\((p \to q) \leftrightarrow ( \sim q \to \sim p)\)is a contradictionCorrect
- B\(p \wedge \sim p\) is a contradiction
- C\(p \vee \sim p\) is a tautology
- D\( \sim ( \sim p) \leftrightarrow p\) is a tautology
7
Which of the following is not a proposition ?
- A5 is an even integer
- B\(\sqrt 2 \) is irrational
- C3 is a prime
- DMathematics is interestingCorrect
8
\((p \wedge \sim q) \wedge ( \sim p \vee q)\) is
- Aboth a tautology and a contradiction
- Ba tautology
- Cneither a tautology nor a contradiction
- Da contradictionCorrect
9
The proposition \((p \to \sim p) \wedge ( \sim p \to p)\) is
- Aa contradictionCorrect
- Bboth a tautology and a contradiction
- Cneither a tautology nor a contradiction
- Da tautology
10
Which of the following statement is a tautology
- A\((p \vee \sim q) \wedge (p \vee q)\)
- B\(( \sim p \vee \sim q) \vee (p \vee q)\)Correct
- C\(( \sim p \vee q) \sim (p \vee \sim q)\)
- D\(( \sim p \vee \sim q) \to (p \vee q)\)
11
Negation of the statement \(p \to (q \wedge r)\) is
- A\(p \wedge ( \sim q \vee \sim r)\)Correct
- B\(p \to ( \sim q \vee r)\)
- C\( \sim p \to ( \sim q \vee r)\)
- D\( \sim p \wedge ( \sim q \vee \sim r)\)
12
Negation of the statement \((p \wedge r) \to (r \vee q)\) is
- A\((p \wedge r) \vee (r \to q)\)
- B\((p \wedge r) \vee ( \sim r \to \sim q)\)
- C\((p \wedge r) \wedge ( \sim r \wedge \sim q)\)Correct
- D\((p \wedge r) \wedge ( \sim r \to \sim q)\)
13
Negation of the statement \(q \vee \sim (p \wedge r)\) is
- A\( \sim q \wedge \sim (p \wedge r)\)
- B\( \sim q \wedge (p \wedge r)\)Correct
- C\( \sim q \vee (p \wedge r)\)
- D\( \sim q \to \sim (p \wedge r)\)
14
Which of the following is always true ?
- A\((p \to q) \cong ( \sim q \to \sim p)\)Correct
- B\( \sim (p \vee q) \cong ( \sim p \vee \sim q)\)
- C\( \sim (p \wedge q) \cong ( \sim p \wedge \sim q)\)
- D\( \sim (p \to q) \cong (p \vee \sim q)\)
15
Negation of the statement \( \sim p \to (q \vee r)\) is
- A\( \sim p \wedge ( \sim q \wedge \sim r)\)Correct
- B\(p \vee (q \wedge r)\)
- C\(p \wedge (q \vee r)\)
- D\(p \to \sim (q \vee r)\)