Probability Test
Probability
This is Probability Test-02 for CBSE class 12 Maths.. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
A coin is tossed three times, if E : head on third toss , F : heads on first two tosses. Find P(E|F)
- A\(\frac{2}{3}\)
- B\(\frac{1}{5}\)
- C\(\frac{1}{2}\)Correct
- D\(\frac{1}{3}\)
2
A coin is tossed three times, if E : at least two heads , F : at most two heads. Find P(E|F)
- A\(\;\frac{2}{3}\)
- B\(\frac{2}{7}\)
- C\(\frac{2}{5}\)
- D\(\frac{3}{7}\)Correct
3
A coin is tossed three times, E : at most two tails , F : at least one tail. Find P(E|F)
- A\(\frac{3}{7}\)
- B\(\frac{2}{7}\)
- C\(\frac{6}{7}\)Correct
- D\(\frac{4}{7}\)
4
A black and a red dice are rolled. Find the conditional probability of obtaining a sum greater than 9, given that the black die resulted in a 5.
- A\(\frac{5}{9}\)
- B\(\frac{1}{3}\)Correct
- C\(\frac{4}{9}\)
- D\(\frac{2}{3}\)
5
A black and a red dice are rolled. Find the conditional probability of obtaining the sum 8, given that the red die resulted in a number less than 4.
- A\(\frac{7}{9}\)
- B\(\frac{5}{9}\)
- C\(\frac{1}{9}\)Correct
- D\(\frac{4}{9}\)
6
An instructor has a question bank consisting of 300 easy True / False questions,200 difficult True / False questions, 500 easy multiple choice questions and 400 difficult multiple choice questions. If a question is selected at random from the question bank, what is the probability that it will be an easy question given that it is a multiple choice question?
- A\(\frac{1}{9}\)
- B\(\frac{4}{9}\)
- C\(\frac{7}{9}\)
- D\(\frac{5}{9}\)Correct
7
Consider the experiment of throwing a die, if a multiple of 3 comes up, throw the die again and if any other number comes, toss a coin. Find the conditional probability of the event ‘the coin shows a tail’, given that ‘at least one die shows a 3’.
- A0Correct
- B0.2
- C0.5
- D1
8
If P(A) = \(\frac{1}{2}\), P(B) = 0, then P(A|B) is
- Anot definedCorrect
- B0
- C1
- D\(\frac{1}{2}\)
9
If A and B are events such that P(A|B) = P(B|A), then
- AP(A) = P(B)Correct
- BA = B
- CA ⊂ B but A ≠ B
- DA ∩ B = \(\emptyset \)
10
If E and F are independent, then
- AP (E ∩ F) = P (E) P (F)Correct
- BP (E ∩ F) = P (E) P (E|F)
- CP (E ∩ F) =P (E ∪ F)
- DP (E ∩ F) = P (E) P (F|E)
11
If E and F are independent, then
- AP (E|F) = P (E), P (F) ≠ 0Correct
- BP (E|F) = P (E’), P (F) ≠ 0E’ is complement of E
- CP (E|F) = P (F), P (F) ≠ 0
- DP (E|F) =P (E’∪ F)E’ is complement of E
12
Let (\({E_1},{\text{ }}{E_2},{\text{ }}...,{\text{ }}{E_n}\)) be a partition of a sample space and suppose that each of \({E_1},{\text{ }}{E_2},{\text{ }}...,{\text{ }}{E_n}\) has nonzero probability. Let A be any event associated with S,then
- AP(A) = P(E0) P (A|E1) + P (E1) P (A|E2) + ... + P (En – 1) P(A|En)
- BP(A) = P(E2) P (A|E1) + P (E2) P (A|E2) + ... + P (En) P(A|En)
- CP(A) = P(E1) P (A|E1) + P (E2) P (A|E2) + ... + P (En) P(A|En)Correct
- DP(A) = P(E1) P (A|E1) + P (E1) P (A|E2) + ... + P (En) P(A|En)
13
If P(A) =\(\frac{6}{{11}}\), P(B) =\(\frac{5}{{11}}\)and P(A ∪ B) =\(\frac{7}{{11}}.\)find P(A∩B)
- A\(\frac{5}{{17}}\)
- B\(\frac{4}{{13}}\)
- C\(\frac{4}{{11}}\)Correct
- D\(\frac{5}{{11}}\)
14
Two events A and B will be independent, if
- AP(A) + P(B) = 1
- BP(A′B′) = [1 – P(A)] [1 – P(B)]Correct
- CA and B are mutually exclusive
- DP(A) = P(B)
15
If P(A) = \(\frac{3}{5}\) and P(B) = \(\frac{1}{5}\), find P (A ∩ B) if A and B are independent events.
- A\(\frac{3}{{25}}\)Correct
- B\(\frac{4}{{25}}\)
- C\(\frac{8}{{25}}\)
- D\(\frac{7}{{25}}\)