Constructions CBSE Questions & Answers
Constructions
This is Mathematics Class 09 Constructions CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
Two or more circles are concentric if they have same
- Adiameter
- BcentreCorrect
- Cradil
- Dnone
2
If two circles touches internally then distance between their centres is equal to
- Anone
- Bdifference of radilCorrect
- Cnot possible to determine
- Dsum of radil
3
Radius of a circle is ________ to tangent
- Aparallel
- Bnone
- CNo relation
- DperpendicularCorrect
4
Two radii of same circle are always :
- Aparallel and may inchired at any angleCorrect
- Bparallel
- Cperpendicular
- Dmay inchired at any angle
5
A quadrilateral can be drawn.If the measures of its
- Afour sides are given
- Bthree sides and a diagonal are given
- Cfour sides and one angle are givenCorrect
- Dfour angles and one side are given
6
The point in the plane of a triangle which is at equal perpendicular distances from the three sides of the triangle is its
- Aorthocenter
- Bcentroid
- Ccircumcentre
- DincentreCorrect
7
The orthocentere of an obtuse angled triangle lies
- Aon the greatest side of the triangle
- Bon the smallest side of the triangle
- Coutside the triangleCorrect
- Dinside the triangle
8
With the help of a ruler and compass. It is possible to construct an angle of
- A\({32.5^0}\)
- B\({42.5^0}\)
- C\({35^0}\)
- D\({22.5^0}\)Correct
9
With the help of a ruler and compass. It is not possible to construct an angle of
- A\({30^0}\)
- B\({45^0}\)
- C\(7{{1 \over 2}^\circ }\)
- D\({70^0}\)Correct
10
The construction of a triangle ABC in which AB = 2.5 cm, \(\angle A = {45^0}\) is not possible when difference of BC and AC is equal to
- A3.0 cmCorrect
- B1.5 cm
- C2 cm
- D1 cm
11
The construction of triangle ABC, given that BC = 5 cm, \(\angle B = {45^0}\) is not possible when difference of AB and AC is equal to
- A4 cm
- B3 cm
- C2 cm
- D5.1 cmCorrect
12
The construction of a triangle ABC, given that BC = 4 cm, \(\angle C = {60^0}\) is possible when difference of AB and AC is equal to
- A3.5 cm.Correct
- B4.2 cm
- C4.5 cm
- D5 cm
13
To construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. We draw line segment AB of 12 cm. Draw a ray AX making \({90^0}\) with AB. The next step is:
- ACut a line segment BD of 18 cm
- BCut a line segment AD of 18 cm on AB
- CCut a line segment AD of 18 cm on AXCorrect
- DCut a line segment BD of 18 cm on AB
14
By following these steps of construction, (i) Draw a line segment PQ = 11 cm (ii) At P construct an angle of \({60^0}\) and at Q, an angle of \({45^0}\), (iii) Bisect these angles. Let the bisectors of these angles intersect at a point A. (iv) Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C. (v). Join AB and AC. Triangle ABC has been obtained. In this \(\)ABC.
- AAB + BC = 11cm
- BBC + CA = 11cm
- CAB + BC + CA = 11cmCorrect
- DAB + BC + CA > 11cm
15
In the construction of the bisector of a given angle, as shown in the figure below \(\triangle BEF \cong \triangle BDF\;by\;which\;congruence\;criterion?\)
- ASSSCorrect
- BRHS
- CSAS
- DAAS