INTRODUCTION TO TRIGONOMETRY Test
INTRODUCTION TO TRIGONOMETRY
This is INTRODUCTION TO TRIGONOMETRY Test-02 for CBSE class 10 Maths.. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
Which of the following is true:
- A\(\frac{{\cos A}}{{\sin A}} = \sec A\)
- B\(\frac{{\sin A}}{{\cos ecA}} = \cot A\)
- C\(\frac{{\sin A}}{{\cos A}} = \tan A\)Correct
- D\(\frac{{\cos ecA}}{{\sin A}} = \cos A\)
2
cot A tan A =
- A1Correct
- Bcot A
- Csec A
- Dtan A
3
Given that \(\sin \theta = \frac{a}{b}\), then \(cos{\text{ }}\theta \) is equal to
- A\(\frac{b}{{\sqrt {{b^2} - {a^2}} }}\)
- B\(\frac{b}{a}\)
- C\(\frac{{\sqrt {{b^2} - {a^2}} }}{b}\)
- D\(\frac{a}{{\sqrt {{b^2} - {a^2}} }}\)Correct
4
The value of \(sin60^\circ cos30^\circ + sin30^\circ cos60^\circ \) is
- A0
- B2
- C– 1
- D1Correct
5
The value of \(2{\text{ }}ta{n^2}45^\circ + {\text{ }}co{s^2}30^\circ \;--\;si{n^2}60^\circ \) is
- A1
- B0
- C2Correct
- D– 2
6
If \(2sin2\theta = \sqrt 3 \) , then the value of is
- A\(60^\circ \)
- B\(45^\circ \)
- C\(0^\circ \)
- D\(30^\circ \)Correct
7
\(\frac{{2\tan 30^\circ }}{{1 + {{\tan }^2}30^\circ }} = \)
- A\(sin60^\circ \)Correct
- B\(\begin{array}{*{20}{l}} {cos60^\circ } \end{array}\)
- Cnone of these
- D\(tan60^\circ \)
8
\(\frac{{1 - {{\tan }^2}45^\circ }}{{1 + {{\tan }^2}45^\circ }} = \)
- A0Correct
- B\(\begin{array}{*{20}{l}} {sin45^\circ } \end{array}\)
- C\(\begin{array}{*{20}{l}} {tan45^\circ } \end{array}\)
- D\(cos45^\circ \)
9
sin 2A = 2 sin A is true when A =
- A\(0^\circ \)Correct
- B\(30^\circ \)
- C\(\begin{array}{*{20}{l}} {45^\circ } \end{array}\)
- D\(60^\circ \)
10
The value of \(\frac{{\tan 30^\circ }}{{\cot 60^\circ }}\) is
- A\(\frac{1}{{\sqrt 2 }}\)
- B\(\frac{1}{{\sqrt 3 }}\)
- C1Correct
- D\(\sqrt 2 \)
11
The value of \(\sin {45^ \circ } + \cos {45^ \circ }\) is
- A\(\frac{1}{{\sqrt 3 }}\)
- B\(\frac{1}{{\sqrt 2 }}\)
- C\(\sqrt 2 \)Correct
- D1
12
\(1 - 2{\sin ^2}30^\circ = \)
- Anone of these
- B\(\begin{array}{*{20}{l}} {cos60^\circ } \end{array}\)Correct
- C\(sin60^\circ \)
- D\(tan60^\circ \)
13
If $~sin\text{ }\theta \text{ }=\frac{1}{2}$ and $cos\phi =\text{ }\frac{1}{2}$ , then the value of ($\theta \text{ }+\phi $ ) is
- A\(\begin{array}{*{20}{l}} {90^\circ } \end{array}\)Correct
- B\(\begin{array}{*{20}{l}} {0^\circ } \end{array}\)
- C\(\begin{array}{*{20}{l}} {60^\circ } \end{array}\)
- D\(\begin{array}{*{20}{l}} {30^\circ } \end{array}\)
14
Given that \(\sin \alpha = \frac{1}{{\sqrt 2 }}\) and \(\cos \beta = \frac{1}{{\sqrt 2 }}\), then the value of \((\alpha + \beta )\) is
- A\(\begin{array}{*{20}{l}} {30^\circ } \end{array}\)
- B\(\begin{array}{*{20}{l}} {45^\circ } \end{array}\)
- C\(\begin{array}{*{20}{l}} {60^\circ } \end{array}\)
- D\(\begin{array}{*{20}{l}} {90^\circ } \end{array}\)Correct
15
If \(\sin \alpha = \frac{1}{{\sqrt 2 }}\) and tan β = 1, then the value of \(\cos (\alpha + \beta )\) is
- A0Correct
- B3
- C1
- D2