TRIANGLES Test
TRIANGLES
This is TRIANGLES Test-05 for CBSE class 10 Maths.. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
If PQR is an isosceles triangle and M is a point on QR such that \(PM \bot QR,\)then
- A\(P{Q^2} + P{M^2} = QM.MR.\)
- B\({\text{P}}{{\text{Q}}^2} - {\text{P}}{{\text{R}}^2}{\text{ = Q}}{{\text{M}}^2}{\text{ }} - {\text{ M}}{{\text{R}}^2}\)Correct
- C\(P{Q^2} - P{M^2} = Q{M^2} - M{R^2}.\)
- D\(P{Q^2} - P{M^2} = QM.MR.\)
2
Two poles of height 8 m and 13 m are standing 12 m apart. The distance between their tops is
- A13 m.Correct
- B15 m.
- C17 m.
- D19 m.
3
The length of the second diagonal of a rhombus whose side is 5 cm and one of the diagonal is 8 cm is
- A6 cm.Correct
- B14 cm
- C12 cm.
- D10 cm.
4
The length of the side of a rhombus whose diagonals are of lengths 24 cm and 10 cm is
- A13 cm.Correct
- B14 cm.
- C17 cm.
- D16 cm.
5
If D is a point on side BC of \(\Delta ABC\)such that BD = CD = AD, then

- A\(B{D^2} + A{D^2} = A{B^2}\)
- B\(AB\;.\;AC = A{D^2}.\)
- C\(C{D^2} + A{D^2} = A{C^2}\)
- D\(A{B^2} + A{C^2} = B{C^2}\)Correct
6
In an equilateral \(\Delta ABC,\;AD \bot BC\;and\;A{D^2} = p.\;B{C^2},\)then p is equal to
- A\(\frac{1}{3}\)
- B\(\frac{1}{2}.\)
- C\(\frac{3}{4}\)Correct
- D\(\frac{2}{3}\)
7
In \(\Delta ABC,AB = 6\sqrt 3 \;cm,\;AC = 12\;cm\;and\;BC\; = \;6\;cm.\)The angle A and B are respectively
- A\({45^0},{45^0}.\)
- B\({60^0},{60^0}.\)
- C\({30^0},{90^0}.\)Correct
- D\({75^0},{30^0}.\)
8
If the length of a diagonal of a square is ‘a’, then its perimeter is
- A2a.
- B\(2\sqrt 2 a.\)Correct
- C4a.
- D\(\sqrt 2 a.\)
9
In \(\Delta PQR,\angle Q = {90^0},PQ = 5\;cm,\;QR = 12cm.\) If \(QS \bot PR,\) then QS is equal to
- A\(\frac{{12}}{5}cm.\)
- B\(\frac{{13}}{5}cm.\)
- C\(\frac{{60}}{{13}}cm.\)Correct
- D\(\frac{{80}}{{13}}cm.\)
10
In an isosceles triangle ABC, if AB = AC = 25 cm and BC = 14 cm, then the measure of the altitude from A on BC is
- A22 cm.
- B18 cm.
- C24 cm.Correct
- D20 cm.
11
In an equilateral triangle ABC if \(AD \bot BC,\) then \(A{D^2}\) is equal to
- A\(2C{D^2}\)
- B\(4C{D^2}.\)
- C\(3C{D^2}.\)Correct
- D\(C{D^2}\)
12
In the isosceles triangle ABC if AC = BC and \(A{B^2} = 2A{C^2}\) then the measure of \(\angle C\)is
- A\({45^0}.\)
- B\({60^0}.\)
- C\({90^0}.\)Correct
- D\({30^0}.\)
13
ABC is an isosceles triangle right-angled at B. Two equilateral triangles are constructed with side BC and AC as shown in figure. If \(ar(\Delta ACE) = 20\;c{m^2}\) then \(ar(\Delta BCD)\)is

- A\(15\;c{m^2}.\)
- B\(10\;c{m^2}\)Correct
- C\(16\;c{m^2}.\)
- D\(12\;c{m^2}.\)
14
In the given figure, the value of x is

- A12 cm.
- B6 cm.
- C15 cm.
- D10 cm.Correct
15
In the given figure ABC is a right-angled triangle right-angled at A. Semicircle are drawn on the sides of \(\Delta ABC.\) Then the area of the shaded region is equal to

- A\(\frac{{ar(\Delta ABC)}}{2}\)
- B\(\frac{{ar(semicircle\;BAC)}}{2}\)
- C\(ar(semicircle\;BAC).\)
- D\(ar(\Delta ABC)\)Correct