Limits And Derivatives CBSE Questions & Answers
Limits And Derivatives
This is Mathematics Class 11 Limits and Derivatives CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
\(\mathop {Lt}\limits_{h \to 0} \;\;\;\;{{\root 3 \of {8 + h} - 2} \over 4}\) is equal to
- A\({1 \over 24}\)
- B\({1 \over 12}\)Correct
- C\({1 \over 3}\)
- Dnone of these
2
If f (x) = \(\sqrt {1 - {x^2}} ,x \in (0,1),thenf'(x)\) is equal to
- A\(\sqrt {{x^2} - 1} \)
- B\({{ - x} \over {\sqrt {1 - {x^2}} }}\)Correct
- C\(\sqrt {1 - {x^2}} \)
- D\({1 \over {\sqrt {1 - {x^2}} }}\)
3
If \(y = {\sin ^{ - 1}}\) x and z = \({\cos ^{ - 1}}\sqrt {1 - {x^2}} ,\) then \({{dy} \over {dz}} = \)
- A1
- B\({{\left| x \right|} \over x}\)Correct
- C- 1
- D\({\tan ^{ - 1}}{x \over {\sqrt {1 - {x^2}} }}\)
4
\({d \over {dx}}\left\{ {{{\tan }^{ - 1}}\left( {{{3x - {x^3}} \over {1 - 3{x^2}}}} \right)} \right\}\) is equal to
- A\({3 \over {1 + {x^2}}}\)Correct
- B\({\sec ^2}3x\)
- C\({1 \over {1 + {x^2}}}\)
- D\({3 \over {1 + 9{x^2}}}\)
5
The function, \(f(x) = {(x - a)^2}\cos {1 \over {x - a}}for\;x \ne a\) and f (a) = 0, is
- Acontinuous but not derivable at x = 0
- Bnone of these
- Cnot continuous at x = a
- Dderivable at x = aCorrect
6
\({d \over {dx}}\left( {{{\cos }^{ - 1}}\left( {{{{x^{ - 1}} - x} \over {{x^{ - 1}} + x}}} \right)} \right)\) is equal to
- A\({2 \over {1 + {x^2}}},x > 0\)Correct
- B\({{ - 2} \over {\sqrt {1 + {x^2}} }}\)
- C\({2 \over {1 + {x^2}}},x > 0\)
- Dnone of these
7
\({d \over {dx}}\left( {{{\sin }^{ - 1}}\left( {{2 \over {{x^{ - 1}} + x}}} \right)} \right)\) is equal to
- A\({2 \over {1 + {x^2}}},0 < \left| x \right| < 1\)Correct
- Bnone of these
- C\({2 \over {\sqrt {1 + {x^2}} }},\left| x \right| < 1\)
- D\({2 \over {\sqrt {1 + {x^2}} }}\)
8
\({d \over {dx}}\left( {{{\tan }^{ - 1}}\left( {{x \over {\sqrt {1 - {x^2}} }}} \right)} \right)\) is equal to
- A\({{ - 1} \over {\sqrt {1 - {x^2}} }}\)
- Bnone of these
- C\({1 \over {1 + {x^2}}}\)
- D\({1 \over {\sqrt {1 - {x^2}} }}\)Correct
9
\({d \over {dx}}\left( {{{\tan }^{ - 1}}\left( {{2 \over {{x^{ - 1}} - x}}} \right)} \right)\) is equal to
- A\({2 \over {1 + {x^2}}},x \ne 0, \pm 1\)Correct
- B\({2 \over {1 + {x^2}}},x \ne 0, \pm 1\)
- C\({{ - 2} \over {\sqrt {1 - {x^2}} }}\)
- Dnone of these
10
If \(\sin x = {t \over {\sqrt {1 + {t^2}} }},then{{dx} \over {dt}}\) is equal to
- A\({1 \over {\sqrt {1 - {t^2}} }}\)
- B\({1 \over {1 + {t^2}}}\)Correct
- C\({1 \over {{{\left( {1 + {t^2}} \right)}^{3/2}}}}\)
- Dnone of these
11
\({d \over {dx}}({\sin ^{ - 1}}x) = {1 \over {\sqrt {1 - {x^2}} }}\) holds true for
- Aall real x
- Ball real x for which | x| > 1
- Call x \(\) ( - 1, 1)Correct
- Dall x \(\) [- 1, 1]
12
Derivative of tan \(\sqrt {{x^2} + 1} \;w.r.t.\sqrt {{x^2} + 1} \) is
- A\({\sec ^2}x\)
- B\({\sec ^2}\sqrt {{x^2} + 1} \)Correct
- Cnone of these
- D\({\sec ^2}\left( {{x \over {\sqrt {{x^2} + 1} }}} \right)\)
13
If \(y = {{1 - x} \over {1 + x}}then\;{y_6} = \)
- A\(\frac{{2\left| \!{\underline {\, 6 \,}} \right. }}{{{{(1 + x)}^7}}}\)Correct
- B\(\frac{{\left| \!{\underline {\, 6 \,}} \right. }}{{{{(1 + x)}^7}}}\)
- C\(\frac{{ - 2\left| \!{\underline {\, 6 \,}} \right. }}{{{{(1 + x)}^7}}}\)
- Dnone of these
14
If y = log \((x + \sqrt {1 + {x^2})} \) then \({{{d^2}y} \over {d{x^2}}} = \)
- A\({{ - x} \over {{{({x^2} + 1)}^{3/2}}}} = \)Correct
- B\({1 \over {\sqrt {{x^2} + 1} }}\)
- C\({x \over {{{({x^2} + 1)}^{3/2}}}}\)
- D\({{ - 2x} \over {{{({x^2} + 1)}^{3/2}}}} = \)
15
If y = log x , then \({y_n} = \)
- A\({{{{( - 1)}^n}.n!} \over {{x^{n + 1}}}}\)
- B\({{{{( - 1)}^n}.n!} \over {{x^n}}}.\)
- C\({{{{( - 1)}^{n - 1}}(n - 1)!} \over {{x^n}}}\)Correct
- D\({{{{( - 1)}^n}(n - 1)!} \over {{x^n}}}\)