Lines And Angles CBSE Questions & Answers
Lines And Angles
This is Mathematics Class 09 Lines and Angles CBSE Questions & Answers. There are 15 questions in this test with each question having around four answer choices.
Questions & Answers
1
In the given figure, \(\angle \)BAC = 40\(^0\), \(\angle \)ACB = 90\(^0\) and \(\angle \)BED = 100\(^0\), Then \(\angle \)BDE = ?

- A25\(^0\)
- B40\(^0\)
- C50\(^0\)
- D30\(^0\)Correct
2
In the given figure, BO and CO are the bisectors of \(\angle \)B and \(\angle \)C respectively. If \(\angle \)A = 50\(^0\), then \(\angle \)BOC = ?

- A130\(^0\)
- B115\(^0\)Correct
- C100\(^0\)
- D120\(^0\)
3
In the given figure, AB \(\parallel \) CD. If \(\angle \)EAB = 50\(^0\) and \(\angle \)ECD = 60\(^0\), then \(\angle \)AEB = ?

- A55\(^0\)
- B60\(^0\)
- C70\(^0\)Correct
- D50\(^0\)
4
In the given figure, \(\angle \)OAB = 75\(^0\), \(\angle \)OBA = 55\(^0\) and \(\angle \)OCD = 100\(^0\). Then \(\angle \)ODC = ?

- A30\(^0\)Correct
- B20\(^0\)
- C35\(^0\)
- D25\(^0\)
5
An angle is one-fifth of its supplement. The measure of the angle is :-

- A30\(^0\)Correct
- B75\(^0\)
- C150\(^0\)
- D15\(^0\)
6
In the given figure, AB \( \parallel \) CD, If \(\angle \)ABO = 45\(^0\) and \(\angle \)COD = 100\(^0\) then \(\angle \)CDO = ?

- A45\(^0\)
- B30\(^0\)
- C25\(^0\)
- D35\(^0\)Correct
7
In the given figure, AB \( \parallel \) DC, \(\angle \)BAD = 90\(^0\), \(\angle \)CBD = 280 and \(\angle \)BCE = 65\(^0\). Then \(\angle \)ABD = ?

- A43\(^0\)
- B53\(^0\)
- C32\(^0\)
- D37\(^0\)Correct
8
For what value of x shall we have l \( \parallel \) m ?

- Ax = 70
- Bx = 60
- Cx = 50Correct
- Dx = 45
9
In the given figure, sides CB and BA of \(\Delta\)ABC have been produced to D and E respectively such that \(\angle \)ABD = 110\(^0\) and \(\angle \)CAE = 135\(^0\). Then \(\angle \)ACB = ?

- A65\(^0\)Correct
- B35\(^0\)
- C55\(^0\)
- D45\(^0\)
10
In \(\Delta\)ABC, BD \( \bot \) AC, \(\angle \)CAE = 30\(^0\) and \(\angle \)CBD = 40\(^0\). Then \(\angle \)AEB = ?

- A80\(^0\)Correct
- B50\(^0\)
- C60\(^0\)
- D70\(^0\)
11
In the given figure, AB \( \parallel \) CD, CD \( \parallel \) EF and y : z = 3 : 7, then x = ?

- A162\(^0\)
- B126\(^0\)Correct
- C108\(^0\)
- D63\(^0\)
12
In the given figure, AB \( \parallel \) CD \( \parallel \) EF, EA \( \bot \) AB and BDE is the transversal such that \(\angle \)DEF = 55\(^0\), Then \(\angle \)AEB = ?

- A35\(^0\)Correct
- B45\(^0\)
- C25\(^0\)
- D55\(^0\)
13
In the given figure, AM \( \bot \)BC and AN is the bisector of \(\angle \)A. If \(\angle \)ABC = 70\(^0\) and \(\angle \)ACB = 20\(^0\), then MAN = ?

- A15\(^0\)
- B20\(^0\)
- C25\(^0\)Correct
- D30\(^0\)
14
The sides BC, CA and AB of \(\Delta\)ABC have been produced to D, E and F respectively as shown in the figure, forming exterior angles \(\angle \)ACD, \(\angle \)BAE and \(\angle \)CBF. Then, \(\angle \)ACD = \(\angle \)BAE + \(\angle \)CBF = ?

- A320\(^0\)
- B240\(^0\)
- C300\(^0\)
- D360\(^0\)Correct
15
The sides BC, BA and CA of \(\Delta\) ABC have been produced to D, E and F respectively, as shown in the give figure, Then, \(\angle \)B ?

- A35\(^0\)
- B75\(^0\)Correct
- C65\(^0\)
- D55\(^0\)